Ordered topological vector space

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In mathematics, specifically in functional analysis and order theory, an ordered topological vector space, also called an ordered TVS, is a topological vector space (TVS) X that has a partial order ≤ making it into an ordered vector space whose positive cone [math]\displaystyle{ C := \left\{ x \in X : x \geq 0\right\} }[/math] is a closed subset of X.[1] Ordered TVS have important applications in spectral theory.

Normal cone

Main page: Normal cone (functional analysis)

If C is a cone in a TVS X then C is normal if [math]\displaystyle{ \mathcal{U} = \left[ \mathcal{U} \right]_{C} }[/math], where [math]\displaystyle{ \mathcal{U} }[/math] is the neighborhood filter at the origin, [math]\displaystyle{ \left[ \mathcal{U} \right]_{C} = \left\{ \left[ U \right] : U \in \mathcal{U} \right\} }[/math], and [math]\displaystyle{ [U]_{C} := \left(U + C\right) \cap \left(U - C\right) }[/math] is the C-saturated hull of a subset U of X.[2]

If C is a cone in a TVS X (over the real or complex numbers), then the following are equivalent:[2]

  1. C is a normal cone.
  2. For every filter [math]\displaystyle{ \mathcal{F} }[/math] in X, if [math]\displaystyle{ \lim \mathcal{F} = 0 }[/math] then [math]\displaystyle{ \lim \left[ \mathcal{F} \right]_{C} = 0 }[/math].
  3. There exists a neighborhood base [math]\displaystyle{ \mathcal{B} }[/math] in X such that [math]\displaystyle{ B \in \mathcal{B} }[/math] implies [math]\displaystyle{ \left[ B \cap C \right]_{C} \subseteq B }[/math].

and if X is a vector space over the reals then also:[2]

  1. There exists a neighborhood base at the origin consisting of convex, balanced, C-saturated sets.
  2. There exists a generating family [math]\displaystyle{ \mathcal{P} }[/math] of semi-norms on X such that [math]\displaystyle{ p(x) \leq p(x + y) }[/math] for all [math]\displaystyle{ x, y \in C }[/math] and [math]\displaystyle{ p \in \mathcal{P} }[/math].

If the topology on X is locally convex then the closure of a normal cone is a normal cone.[2]

Properties

If C is a normal cone in X and B is a bounded subset of X then [math]\displaystyle{ \left[ B \right]_{C} }[/math] is bounded; in particular, every interval [math]\displaystyle{ [a, b] }[/math] is bounded.[2] If X is Hausdorff then every normal cone in X is a proper cone.[2]

Properties

  • Let X be an ordered vector space over the reals that is finite-dimensional. Then the order of X is Archimedean if and only if the positive cone of X is closed for the unique topology under which X is a Hausdorff TVS.[1]
  • Let X be an ordered vector space over the reals with positive cone C. Then the following are equivalent:[1]
  1. the order of X is regular.
  2. C is sequentially closed for some Hausdorff locally convex TVS topology on X and [math]\displaystyle{ X^{+} }[/math] distinguishes points in X
  3. the order of X is Archimedean and C is normal for some Hausdorff locally convex TVS topology on X.

See also

References

  1. 1.0 1.1 1.2 Schaefer & Wolff 1999, pp. 222–225.
  2. 2.0 2.1 2.2 2.3 2.4 2.5 Schaefer & Wolff 1999, pp. 215–222.